How do you expand #(2+b^2)^4#? Precalculus The Binomial Theorem Pascal's Triangle and Binomial Expansion 1 Answer t0hierry Dec 27, 2016 #2 + b^2)^4 = 2b^8 + 4 *2* b^6 + 6*4*b^4+ 4 *8 *b^2 + 2^4# Explanation: #(2 + b^2)^4 = 2b^8 + 4 *2* b^6 + 6*4*b^4+ 4 *8 *b^2 + 2^4# Answer link Related questions What is Pascal's triangle? How do I find the #n#th row of Pascal's triangle? How does Pascal's triangle relate to binomial expansion? How do I find a coefficient using Pascal's triangle? How do I use Pascal's triangle to expand #(2x + y)^4#? How do I use Pascal's triangle to expand #(3a + b)^4#? How do I use Pascal's triangle to expand #(x + 2)^5#? How do I use Pascal's triangle to expand #(x - 1)^5#? How do I use Pascal's triangle to expand a binomial? How do I use Pascal's triangle to expand the binomial #(a-b)^6#? See all questions in Pascal's Triangle and Binomial Expansion Impact of this question 1499 views around the world You can reuse this answer Creative Commons License