How do you expand the binomial (x-2)^3(x−2)3?

1 Answer
Narad T.
Oct 16, 2016

(x-2)^3 =x^3-6x^2+12x-8(x−2)3=x3−6x2+12x−8

Explanation:

(x-2)^3 =x^3+(""_1^3)x^2(-2)+(""_2^3)x(-2)^2+(-2^3)(x−2)3=x3+(31)x2(−2)+(32)x(−2)2+(−23)

(""_1^3)=(3*2*1)/2=3(31)=3⋅2⋅12=3
(""_2^3)=(3*2*1)/2=3(32)=3⋅2⋅12=3
You can also use Pascal's triangle
So the answer is
(x-2)^3 =x^3-6x^2+12x-8(x−2)3=x3−6x2+12x−8

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