How do you expand the binomial ${(x - 2)}^{3}$ $(x-2)^3$ using the binomial theorem?

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Answer 1 · 2016-10-18T19:12:51

$= x^{3} - 6 x^{2} + 12 x - 8$ $=x^3-6x^2+12x-8$

Use the binomial expansion or Pascal's triangle(1 3 3 1)
$(x-2)^3=x^3+³C₁x^2(-2)+³C₂x(-2)^2+(-2)^3$
$=x^3-3*2*x^2+3*4*x-8$
$=x^3-6x^2+12x-8$

How do you expand the binomial (x-2)^3(x−2)3(x-2)^3 using the binomial theorem?