Question

How do you expand `(z+1/z)^8`?

Answer 1

Expansion given below

Explanation:

Using binomial expansion as follows

`(z+1/z)^8`

`=^8C_0z^8+^8C_1z^7(1/z)+^8C_2z^6(1/z)^2+\ldots +^8C_8(1/z)^8`