How do you factor $100m^8 - 9$ ?

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Answer 1 · 2015-05-06T21:08:43

This fits the form of the difference of squares.

$a^2-b^2=(a-b)(a+b)$

$100m^8-9=(10m^4)^2-3^2$

$a=10m$
$b=3$

$100m^8-9=(10m^4-3)(10m^4+3)$

How do you factor 100m^8 - 9100m^8 - 9?