How do you factor $10 m^{3} + 2 m^{2} - 36 m$ $10m^3+2m^2-36m$ ?

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Answer 1 · 2018-03-10T11:41:05

See a solution process below:

First, factor a common term of $2 m$ $2m$ out of each individual term:

$(2 m \cdot 5 m^{2}) + (2 m \cdot m) - (2 m \cdot 18) \Rightarrow$ $(2m * 5m^2) + (2m * m) - (2m * 18) =>$

$2 m (5 m^{2} + m - 18)$ $2m(5m^2 + m - 18)$

Next, factor the quadratic as:

$2 m (5 m - 9) (m + 2)$ $2m(5m - 9)(m + 2)$

Answer 2 · 2018-03-10T11:46:33

$2 m (m + 2) (5 m - 9)$ $2m(m+2)(5m-9)$

$10 m^{3} + 2 m^{2} - 36 m = 2 m (5 m^{2} + m - 18)$ $10m^3+2 m^2-36m =2m(5m^2+m-18)$

$= 2 m (5 m^{2} + 10 m - 9 m - 18)$ $=2m(5m^2+10m-9m-18)$

$= 2 m {5 m (m + 2) - 9 (m + 2)}$ $=2m{5m(m+2)-9(m+2)}$

$= 2 m (m + 2) (5 m - 9)$ $=2m(m+2)(5m-9)$ [ Ans]

How do you factor 10m^3+2m^2-36m10m3+2m2−36m10m^3+2m^2-36m?