How do you factor $10 x^{2} - 20 x y + 10 y^{2}$ $10x^2-20xy+10y^2$ ?

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Answer 1 · 2017-02-03T11:12:30

The answer is $= 10 {(x - y)}^{2}$ $=10(x-y)^2$

We need

${(a - b)}^{2} = a^{2} - 2 a b + b^{2}$ $(a-b)^2=a^2-2ab+b^2$

So,

$10 x^{2} - 20 x y + 10 y^{2}$ $10x^2-20xy+10y^2$

$= 10 (x^{2} - 2 x y + y^{2})$ $=10(x^2-2xy+y^2)$

$= 10 (x - y) (x - y)$ $=10(x-y)(x-y)$

$= 10 {(x - y)}^{2}$ $=10(x-y)^2$

How do you factor 10x^2-20xy+10y^210x2−20xy+10y210x^2-20xy+10y^2?