How do you factor $10x^2+35x-4x-14$ by grouping?

Question

2394 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-30T19:03:48

$10x^2+35x-4x-14 = (5x-2)(2x+7)$

Note that $10x^2$ and $35x$ are both divisible by $5x$ and $4x$ and $14$ are both divisible by $2$ .

So we find:

$10x^2+35x-4x-14 = (10x^2+35x)-(4x+14)$

$color(white)(10x^2+35x-4x-14) = 5x(2x+7)-2(2x+7)$

$color(white)(10x^2+35x-4x-14) = (5x-2)(2x+7)$

Answer 2 · 2018-03-30T19:06:43

$10x^2+35x−4x−14$

$=>5x(2x+7)−2(2x+7)$

$=>(5x−2)(2x+7)$

$color(white)(dd$

Verification,

$(5x−2)(2x+7)$

$=>5x(2x+7)−2(2x+7)$

$=>10x^2+35x−4x−14$

How do you factor 10x^2+35x-4x-1410x^2+35x-4x-14 by grouping?