How do you factor 10x^2 + 5 + 27x?

1 Answer
Jun 6, 2016

(2x+5)(5x+1)

Explanation:

let's first solve the equation:
10x^2+27x+5=0

and find the zeroes

x=(-27+-sqrt(27^2-4*10*5))/(2*10)
then
x=(-27+-sqrt(729-200))/(20)
x=(-27+-23)/(20)
x=-5/2 and x=-1/5

let's factor
10x^2+27x+5=10(x+5/2)(x+1/5)

let's eliminate fractions by multiplying :
2(x+5/2)5(x+1/5)
(2x+5)(5x+1)