How do you factor $11 x^{2} + 11 x y + 4 x + 4 y$ $11x^2+11xy+4x+4y$ ?

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How do you factor $11 x^{2} + 11 x y + 4 x + 4 y$ $11x^2+11xy+4x+4y$ ?

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Answer 1 · 2018-03-18T10:52:33

A bit rusty with factoring, but I'm pretty sure...

Explanation:

$11 x^{2} + 11 x y + 4 x + 4 y$ $11x^2 + 11xy + 4x + 4y$

(Use grouping.)

$11 (11 x^{2} + 11 x y) + 4 (4 x + 4 y)$ $11(11x^2 + 11xy) + 4(4x + 4y)$

$(x + y) (11 x + 4)$ $(x + y)(11x + 4)$

Answer 2 · 2018-03-18T11:08:51

$(x + y) (11 x + 4)$ $(x+y)(11x+4)$

Explanation:

$factorise in groups$ $"factorise in groups"$

$11 x (x + y) + 4 (x + y)$ $color(red)(11x)(x+y)color(red)(+4)(x+y)$

$take out common factor (x + y)$ $"take out "color(blue)"common factor "(x+y)$

$= (x + y) (11 x + 4)$ $=(x+y)(color(red)(11x+4))$

$\Rightarrow 11 x^{2} + 11 x y + 4 x + 4 y = (x + y) (11 x + 4)$ $rArr11x^2+11xy+4x+4y=(x+y)(11x+4)$

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How do you factor $11 x^{2} + 11 x y + 4 x + 4 y$ $11x^2+11xy+4x+4y$ ?

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Explanation:

Explanation:

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How do you factor 11x^2+11xy+4x+4y11x2+11xy+4x+4y11x^2+11xy+4x+4y?

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Explanation:

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How do you factor $11 x^{2} + 11 x y + 4 x + 4 y$ $11x^2+11xy+4x+4y$ ?