How do you factor $12x^2-39x+9$ ?

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Answer 1 · 2017-08-07T03:17:16

We can play with factors of 12 (1x12, 2x6, 3,4) and factors of 9 (1x9, 3x3) to combine and factor the expression as:

$(12x - 3)(x - 3)$

Answer 2 · 2017-08-07T08:14:29

$3(4x-1)(x-3)$

$12x^2 -39x+9$

Take out a common factor of $3$ first

$3(4x^2-13x+3)$

Find factors of $4 and 3$ whose products ADD to 13.

$(4xx3)+(1xx1) =13$

$3(4x-1)(x-3)$

How do you factor 12x^2-39x+912x^2-39x+9?