How do you factor $12 x^{3} + 8 x^{2} - x - 1 = 0$ $12x^3+8x^2 -x-1=0$ ?

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Answer 1 · 2016-02-24T10:08:26

It is ${(2 x + 1)}^{2} \cdot (3 x - 1) = 0$ $(2x+1)^2*(3x-1)=0$

Rewrite this as follows

$12x^3+8x^2 -x-1=0=>12x^3+12x^2-4x^2-4x+3x-1=0=> (4x^2+4x+1)*3x-(4x^2+4x+1)=0=> (4x^2+4x+1)*(3x-1)=0=> (2x+1)^2*(3x-1)=0$

How do you factor 12x^3+8x^2 -x-1=012x3+8x2−x−1=0 12x^3+8x^2 -x-1=0?