How do you factor $12y^3+28y-3y-7$ ?

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Answer 1 · 2015-05-03T07:10:17

We can factorise this expression by making Groups of two terms:

$(12y^3+28y)-(3y+7)$

$= 4y(3y + 7) - 1(3y + 7)$

$3y+7$ is a common factor to both the terms

$= color(green)((3y+7)(4y - 1)$

How do you factor 12y^3+28y-3y-712y^3+28y-3y-7?