How do you factor $13(x^6+ 1)^4$ ?

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Answer 1 · 2018-01-24T16:59:00

$13 (x^2+1)^4 (x^4 - x^2 + 1)^4$

$a^3 + b^3 = (a+b)(a^2-ab+b^2)$
$=> x^6 + 1 = (x^2 + 1)(x^4 - x^2 + 1)$
$=> 13(x^6+1)^4 = 13 (x^2+1)^4 (x^4 - x^2 + 1)^4$

How do you factor 13(x^6+ 1)^413(x^6+ 1)^4?