How do you factor $16 - 4 a^{2}$ $16-4a^2$ ?

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Answer 1 · 2015-05-17T08:34:44

property :
$a^{2} - b^{2} = (a + b) (a - b)$ $color(blue)(a^2 - b^2 = (a+b)(a-b)$

expression given is:
$16 - 4 a^{2}$ $16 - 4a^2$
$= 4^{2} - {(2 a)}^{2}$ $= 4^2 - (2a)^2$
here , $a = 4 and b = 2 a$ $a = 4 and b = 2a$

rewriting the expression:
$4^{2} - {(2 a)}^{2} = (4 + 2 a) (4 - 2 a)$ $4^2 - (2a)^2 = (4+2a)(4-2a)$ , this is the factorised form.

How do you factor 16-4a^2 16−4a216-4a^2 ?