How do you factor $16 a^{2} - 56 a + 49$ $16a^2-56a+49$ ?

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How do you factor $16 a^{2} - 56 a + 49$ $16a^2-56a+49$ ?

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Answer 1 · 2016-08-13T12:55:17

$= (4 a - 7) (4 a - 7)$ $=(4a-7)(4a-7)$

Explanation:

$16 a^{2} - 56 a + 49$ $16a^2-56a+49$
$= {(4 a)}^{2} - 2 \times 4 a \times 7 + {(7)}^{2}$ $=(4a)^2-2times4atimes7+(7)^2$
$= {(4 a - 7)}^{2}$ $=(4a-7)^2$
$= (4 a - 7) (4 a - 7)$ $=(4a-7)(4a-7)$

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How do you factor $16 a^{2} - 56 a + 49$ $16a^2-56a+49$ ?

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How do you factor 16a^2-56a+4916a2−56a+49 16a^2-56a+49?

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How do you factor $16 a^{2} - 56 a + 49$ $16a^2-56a+49$ ?