How do you factor $16 z^{2} - 24 z + 9$ $16z^2 - 24z + 9$ ?

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How do you factor $16 z^{2} - 24 z + 9$ $16z^2 - 24z + 9$ ?

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Answer 1 · 2015-09-26T21:33:38

$16 z^{2} - 24 z + 9 = {(4 z - 3)}^{2}$ $16z^2−24z+9=(4z-3)^2$

Explanation:

$16 z^{2} - 24 z + 9 \Rightarrow$ $16z^2−24z+9=>$ use: $a^{2} - 2 a b + b^{2} = {(a - b)}^{2} :$ $a^2-2ab+b^2=(a-b)^2:$ where $: a = 4 z, b = 3 :$ $:a=4z,b=3:$
$= {(4 z - 3)}^{2}$ $=(4z-3)^2$

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How do you factor $16 z^{2} - 24 z + 9$ $16z^2 - 24z + 9$ ?

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