How do you factor $18h^(2)+15h-18$ ?

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Answer 1 · 2018-04-12T05:37:45

$3(2h+3)(3h-2)$

$18h^2+15h-18$ = $(6x+9)(3h-2)$ = $3(2h+3)(3h-2)$

Answer 2 · 2018-04-12T05:49:37

$3(3h-2)(2h+3)$

Given -

$18h^2+15h-18$

$3(6h^2+5h-6)$

$3(6h^2+9h-4h-6)$

$3(3h(2h+3)-2(2h+3)$

$3(3h-2)(2h+3)$

How do you factor 18h^(2)+15h-1818h^(2)+15h-18?