How do you factor $18x^2-2$ ?

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Answer 1 · 2017-06-20T07:44:58

$2(3x+1)(3x-1)$

First look for common factors

$18x^2-2=2(9x^2-1)$

then see if the bracket can be factorised

we note difference of squares hence

$2(9x^2-1)=2(3x+1)(3x-1)$

Answer 2 · 2017-06-20T07:46:03

$= 2(3x+1)(3x-1)$

Always look for a common factor first. IN this case it is $2$

$18x^2 -2 = 2(9x^2-1)" "larr$ difference of squares

$= 2(3x+1)(3x-1)$

Note that:

$x^2-y^2 = (x+y)(x-y)$

How do you factor 18x^2-218x^2-2?