How do you factor $18 x^{2} + 3 x - 10$ $18x^2+3x-10$ by grouping?

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How do you factor $18 x^{2} + 3 x - 10$ $18x^2+3x-10$ by grouping?

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Answer 1 · 2016-05-11T16:51:35

$18 x^{2} + 3 x - 10 = (3 x - 2) (6 x + 5)$ $18x^2+3x-10=(3x-2)(6x+5)$

Explanation:

You need to find how to split the middle term first.

Use an AC Method:

Look for a pair of factors of $A C = 18 \cdot 10 = 180$ $AC=18*10=180$ which differ by $B = 3$ $B=3$ .

The pair $15, 12$ $15, 12$ works in that $15 \times 12 = 180$ $15xx12=180$ and $15 - 12 = 3$ $15-12=3$ .

Use this pair to split the middle term and factor by grouping:

$18 x^{2} + 3 x - 10$ $18x^2+3x-10$

$= 18 x^{2} + 15 x - 12 x - 10$ $=18x^2+15x-12x-10$

$= (18 x^{2} + 15 x) - (12 x + 10)$ $=(18x^2+15x)-(12x+10)$

$= 3 x (6 x + 5) - 2 (6 x + 5)$ $=3x(6x+5)-2(6x+5)$

$= (3 x - 2) (6 x + 5)$ $=(3x-2)(6x+5)$

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How do you factor $18 x^{2} + 3 x - 10$ $18x^2+3x-10$ by grouping?

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Explanation:

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