How do you factor $2(5x+1)^2 - 18$ ?

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Answer 1 · 2016-06-29T01:35:35

First factor out the greatest common factor.

$=2((5x + 1)^2 -9)$

Now you have a difference of squares: $a^2 - b^2 = (a + b)(a - b)$

$=2(5x + 1 + 3)(5x + 1 - 3)$

$=2(5x + 4)(5x - 2)$

Hopefully this helps!

How do you factor 2(5x+1)^2 - 182(5x+1)^2 - 18?