How do you factor $2(x - 2y)^2- 4x(x - 2y)$ ?

Question

3417 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-26T08:40:59

$2(x - 2y)^2- 4x(x - 2y)= color(green)(-2(x-2y)(x+2y)$

$2(x - 2y)^2- 4x(x - 2y)$

In the given expression, we can see that the Binomial $x-2y$ and the number 2 are common to both the terms. Taking this common factor out, we get:

$2(x-2y){(x-2y) - 2x}$

$= 2(x-2y){x - 2y - 2x}$

$= 2(x-2y){(x-2x) - 2y}$

$= 2(x-2y){-x-2y}$

$= 2(x-2y){-(x+2y)}$

$= color(green)(-2(x-2y)(x+2y)$

This is the completely factorised form of the given expression

How do you factor 2(x - 2y)^2- 4x(x - 2y)2(x - 2y)^2- 4x(x - 2y)?