How do you factor $200 m^{4} + 80 m^{3} + 8 m^{2}$ $200m^4 + 80m^3 + 8m^2$ ?

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How do you factor $200 m^{4} + 80 m^{3} + 8 m^{2}$ $200m^4 + 80m^3 + 8m^2$ ?

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Answer 1 · 2016-03-22T23:20:39

$8 m^{2} {(5 m + 1)}^{2}$ $8m^2(5m+1)^2$

Explanation:

In order to factor $200 m^{4} + 80 m^{3} + 8 m^{2}$ $200m^4+80m^3+8m^2$

We begin be taking a common factor from each term
in this case $8 m^{2}$ $8m^2$ will go in to each term.

$8 m^{2} (25 m^{2} + 10 m + 1)$ $8m^2(25m^2+10m+1)$

We can now factor the trinomial using the factors of the first and third term.
$25 m^{2}$ $25m^2$ factors to $(5 m) (5 m)$ $(5m)(5m)$
$1$ $1$ factors to $(1) (1)$ $(1)(1)$

$8 m^{2} (5 m + 1) (5 m + 1)$ $8m^2(5m+1)(5m+1)$

$8 m^{2} {(5 m + 1)}^{2}$ $8m^2(5m+1)^2$

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How do you factor $200 m^{4} + 80 m^{3} + 8 m^{2}$ $200m^4 + 80m^3 + 8m^2$ ?

1 Answer

Explanation:

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How do you factor $200 m^{4} + 80 m^{3} + 8 m^{2}$ $200m^4 + 80m^3 + 8m^2$ ?