How do you factor $20 x^{3} - 125 x = 0$ $20x^3-125x=0$ ?

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How do you factor $20 x^{3} - 125 x = 0$ $20x^3-125x=0$ ?

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Answer 1 · 2016-08-02T11:32:22

$5 x (2 x - 5) (2 x + 5)$ $5x(2x-5)(2x+5)$

Explanation:

Factor out as much as you can from both

$5 x (4 x^{2} - 25)$ $5x(4x^2-25)$

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Consider the example
$a^{2} - b^{2} = (a - b) (a + b)$ $a^2-b^2 = (a-b)(a+b)$
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Applying the method in the example

Write as: $5 x [{(2 x)}^{2} - 5^{2}]$ $" "5x[ (2x)^2-5^2]$ giving:

$5 x (2 x - 5) (2 x + 5)$ $5x(2x-5)(2x+5)$

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How do you factor $20 x^{3} - 125 x = 0$ $20x^3-125x=0$ ?

1 Answer

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Science

Math

Humanities

... and beyond

How do you factor 20x3−125x=020x^3-125x=0?

1 Answer

Explanation:

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Impact of this question

How do you factor $20 x^{3} - 125 x = 0$ $20x^3-125x=0$ ?