How do you factor $25 n^{2} - 20 m n + 4 m^{2}$ $25n^2 - 20mn + 4m^2$ ?

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Answer 1 · 2018-05-10T11:43:37

${(5 n - 2 m)}^{2}$ $(5 n -2 m)^2$

$25 n^{2} - 20 m n + 4 m^{2}$ $25 n^2 -20 m n +4 m^2$

$= 25 n^{2} - 10 m n - 10 m n + 4 m^{2}$ $= 25 n^2 -10 m n -10 m n+4 m^2$

$= 5 n (5 n - 2 m) - 2 m (5 n - 2 m)$ $=5 n (5 n -2 m) - 2 m( 5 n - 2 m)$

$= (5 n - 2 m) (5 n - 2 m)$ $= (5 n -2 m) (5 n- 2 m)$

$= {(5 n - 2 m)}^{2}$ $= (5 n -2 m)^2$ [Ans]

How do you factor 25n2−20mn+4m225n^2 - 20mn + 4m^2?