How do you factor $2x^2 - 10x - 12$ ?

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Answer 1 · 2015-12-29T17:10:26

$(2x+2)(x -6)$ is the factorised form of the expression.

$2x^2 -10x-12$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $ax^2 + bx + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c = 2*-12 = -24$

AND

$N_1 +N_2 = b = -10$

After trying out a few numbers we get $N_1 = -12$ and $N_2 =2$

$2*-12 = -24$ , and $2+(-12)= -10$

$2x^2 -10x-12 = 2x^2 -12x +2x-12$

$=2x(x -6) +2(x-6)$

$=(2x+2)(x -6)$

How do you factor 2x^2 - 10x - 122x^2 - 10x - 12?