How do you factor $2x^2 + 10x + 12 = 0$ ?

Question

10156 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-10T15:35:52

$color(blue)((2x+4)(x+3)$ is the factorised form for the expression.

$2x^2+10x+12=0$

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $ax^2 + bx + c$ , we need to think of 2 numbers such that:

$N_1*N_2 = a*c =2*12 = 24$

and,

$N_1 +N_2 = b = 10$

After trying out a few numbers we get $N_1 = 6$ and $N_2 =4$
$6*4 = 24$ , and $6+4=10$

$2x^2+color(blue)(10x)+12= 2x^2+color(blue)(6x +4x)+12$

$=2x(x+3) + 4(x+3)$

$color(blue)((2x+4)(x+3)$ is the factorised form for the expression.

How do you factor 2x^2 + 10x + 12 = 02x^2 + 10x + 12 = 0?