How do you factor $2x^2+ 11x + 5$ ?

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Answer 1 · 2015-05-28T19:42:01

I'll use a version of the AC Method.

The coefficients are $A=2$ , $B=11$ , $C=5$ (ignoring any signs).

Since the sign on the constant term is $+$ , look for a pair of factors of $AC=10$ , whose sum is $11$ . The pair $1, 10$ works.

Then use that pair to split the middle term and factor by grouping:

$2x^2+11x+5 = 2x^2+x+10x+5$

$=(2x^2+x)+(10x+5)$

$=x(2x+1)+5(2x+1)$

$=(x+5)(2x+1)$

How do you factor 2x^2+ 11x + 52x^2+ 11x + 5?