How do you factor $2x^2 + 14x - 16$ ?

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Answer 1 · 2015-09-28T01:46:19

$2x^2+14x-16=(2x-2)(x+8)$

First you factorise the entire polynomial by 2
$2(x^2+7x-8)$

Then, you would like to find two numbers that add together to give $+7$ and multiply together to give $-8$ .

You will find these two numbers are +8 and -1.

Use that information to factorise the expression.
$2(x-1)(x+8)$

Finally, Multiply the 2 back into one of the brackets.

$(2x-2)(x+8)$

Hope that helps

Answer 2 · 2015-09-28T01:51:48

$2x^2+14x-16=color(red)(2(x-1)(x+8))$

$2x^2+14x-16$

Factor out the GCF $2$ .

$2(x^2+7x-8)$

Factor $(x^2+7x-8)$ .

Find two numbers that when added equal $7$ and when multiplied equal $-8$ . The numbers $-1$ and $8$ fit the criteria.

$(x^2+7x-8)=color(red)((x-1)color(red)((x+8)$

$2x^2+14x-16=color(red)(2(x-1)(x+8))$

How do you factor 2x^2 + 14x - 162x^2 + 14x - 16?