How do you factor $2x^2 + 17x - 9$ ?

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Answer 1 · 2018-04-11T21:14:38

$[x- ((-17 + sqrt106)/4]*[x-((-17 - sqrt106)/4]$

with the discriminant
$D = 17^2 - 4*2(-9)= 34+72 = 106$
$x1,2= (-17 +- sqrt106)/4$

How do you factor 2x^2 + 17x - 92x^2 + 17x - 9?