How do you factor $2 x^{2} + 22 x + 56$ $2x^2+22x+56$ ?

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How do you factor $2 x^{2} + 22 x + 56$ $2x^2+22x+56$ ?

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Answer 1 · 2017-05-14T09:42:50

$2 (x + 4) (x + 7)$ $2(x+4)(x+7)$

Explanation:

$take out a common factor of 2$ $"take out a "color(blue)"common factor"" of 2"$

$\Rightarrow 2 (x^{2} + 11 x + 28)$ $rArr2(x^2+11x+28)$

$to factor the quadratic 'split' the x term$ $"to factor the quadratic 'split' the x term"$

$that is x^{2} + 4 x + 7 x + 28$ $"that is " x^2+4x+7x+28$

$factorising each 'pair' gives$ $"factorising each 'pair' gives"$

$x (x + 4) + 7 (x + 4)$ $color(red)(x)(x+4)color(red)(+7)(x+4)$

$take out the common factor (x + 4)$ $"take out the common factor " (x+4)$

$(x + 4) (x + 7)$ $(x+4)(color(red)(x+7))$

$\Rightarrow 2 x^{2} + 22 x + 56 = 2 (x + 4) (x + 7)$ $rArr2x^2+22x+56=2(x+4)(x+7)$

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How do you factor $2 x^{2} + 22 x + 56$ $2x^2+22x+56$ ?

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How do you factor $2 x^{2} + 22 x + 56$ $2x^2+22x+56$ ?