How do you factor 2x^2-2x-842x2−2x−84?

2 Answers
Yitong L.
Jun 25, 2016

2(x^2-x-42)2(x2−x−42)

Explanation:

when factorising you find a common multiple of all the digits. In this case we have 22. xx does not go into 8484. We then use factorisation 2(x^2-x-42)2(x2−x−42).

Double checking our work
2(x^2)= 2x^22(x2)=2x2
2(x)= 2x2(x)=2x
2(42) = 82(42)=8

Therefore = 2x^2-2x-842x2−2x−84

Nghi N.
Jun 25, 2016

2(x + 6)(x - 7)

Explanation:

y = 2(x^2 - x - 42).y=2(x2−x−42).
Factor the trinomial in parentheses.
Find 2 numbers knowing their sum (b = -1) and their product (c = -42)
They are: 6 and -7.
Sum: 6 - 7 = -1
Product: 6(-7) = -42
y = 2(x + 6)(x - 7)

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