How do you factor $2 x^{2} + 3 x + 4$ $2x^2+3x+4$ ?

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How do you factor $2 x^{2} + 3 x + 4$ $2x^2+3x+4$ ?

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Answer 1 · 2015-10-28T05:28:41

This cannot be factored

Explanation:

There are no numbers which $4$ $4$ and $2$ $2$ can multiply together and add/subtract to $3$ $3$ . However, it can be solved by using the quadratic formula $\frac{- b \pm \sqrt{b^{2} - 4 (a) (c)}}{2 (a)}$ $(-b+-sqrt(b^2-4(a)(c)))/(2(a))$ where $a$ $a$ is $2$ $2$ , $b$ $b$ is $3$ $3$ and $c$ $c$ is $4$ $4$

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How do you factor $2 x^{2} + 3 x + 4$ $2x^2+3x+4$ ?

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How do you factor $2 x^{2} + 3 x + 4$ $2x^2+3x+4$ ?