How do you factor $2 x^{2} - 5 x - 3$ $2x^2 - 5x - 3$ ?

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Answer 1 · 2016-05-21T08:17:30

$(2 x + 1) (x - 3)$ $(2x + 1)(x-3)$

Multiply a and c. Find two numbers that add to b and multiply to ac

$2 \cdot - 3 = - 6$ $2 * -3 = -6$

$- 6 + 1 = - 5$ $-6 + 1 = -5$
$- 6 \cdot 1 = - 6$ $-6 *1 = -6$

Re-write equation with these numbers
$2 x^{2} - 6 x + x - 3$ $2x^2 -6x +x -3$

Factorise that equation
$2 x (x - 3) + 1 (x - 3)$ $2x(x-3) +1(x-3)$

Therefore the answer is;

$(2 x + 1) (x - 3)$ $(2x + 1)(x-3)$

How do you factor 2x2−5x−3 2x^2 - 5x - 3?