How do you factor $2 x^{2} + 5 x - 3$ $2x^2 + 5x - 3$ ?

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Answer 1 · 2016-05-21T10:11:54

$(2 x + 1) (x - 3)$ $(2x+1)(x-3)$

$(2 x + 1) (x - 3)$ $(2x+1)(x-3)$

then you can solve for $x$ $x$ :

$x = - \frac{1}{2}$ $x=-1/2$

$x = 3$ $x=3$

How do you factor 2x^2 + 5x - 32x2+5x−32x^2 + 5x - 3?