How do you factor $2 x^{2} - 6 x - 8$ $2x^2-6x-8$ ?

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Answer 1 · 2015-05-12T00:22:57

$f (x) = 2 (x^{2} - 3 x - 4) .$ $f(x) = 2(x^2 - 3x - 4).$

Factor the trinomial.

Since (a - b + c) = 0, one factor is (x + 1) and the other is (x - 4)

f(x) = 2(x + 1)(x - 4).

How do you factor 2x2−6x−82x^2-6x-8?