How do you factor $2 x^{2} + x - 6$ $2x^2 + x - 6$ ?

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Answer 1 · 2015-06-13T11:14:10

$2 x^{2} + x - 6 = (2 x - 3) (x + 2)$ $2x^2+x-6 = (2x-3)(x+2)$

Let $f (x) = 2 x^{2} + x - 6$ $f(x) = 2x^2+x-6$ .

Notice that $f (- 2) = 8 - 2 - 6 = 0$ $f(-2) = 8-2-6 = 0$ , so $(x + 2)$ $(x+2)$ is a factor.

The other factor must be $(2 x - 3)$ $(2x-3)$ to get the coefficient of $x^{2}$ $x^2$ and the constant term when we multiply them...

$2 x^{2} + x - 6 = (2 x - 3) (x + 2)$ $2x^2+x-6 = (2x-3)(x+2)$

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