How do you factor $2 x^{2} - x + 6$ $2x^2-x+6$ ?

Question

3429 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-23T11:32:52

$x (2 x - 1) + 6$ $x(2x-1)+6$ =0

$2 x^{2} - x + 6 = 0$ $2x^2-x+6=0$
$x (2 x - 1) + 6 = 0$ $x(2x-1)+6=0$
$x \cdot 2 x = 2 x^{2}$ $x*2x=2x^2$
$x \cdot - 1 = - x$ $x*-1=-x$

How do you factor 2x^2-x+62x2−x+62x^2-x+6?