How do you factor $2x³-3x²-2x+3$ ?

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Answer 1 · 2015-12-30T04:20:02

See the following solution

$2x^3$ - $3x^2$ - 2x + 3
= $x^2$ (2x - 3) - 1(2x - 3)
= ( $x^2$ - 1)(2x - 3)
= (x + 1)(x - 1)(2x - 3)

How do you factor 2x³-3x²-2x+32x³-3x²-2x+3?