How do you factor $2 x^{4} - 32 y^{4}$ $2x^4-32y^4$ ?

Question

How do you factor $2 x^{4} - 32 y^{4}$ $2x^4-32y^4$ ?

1 Answer

Impact of this question

3461 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-02T21:26:49

$2 x^{4} - 32 y^{4} = 2 (x - 2 y) (x + 2 y) (x^{2} + 4 y^{2})$ $2x^4-32y^4 = 2(x-2y)(x+2y)(x^2+4y^2)$

Explanation:

The difference of squares identity can be written:

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2-b^2 = (a-b)(a+b)$

Hence we find:

$2 x^{4} - 32 y^{4} = 2 (x^{4} - 16 y^{4})$ $2x^4-32y^4 = 2(x^4-16y^4)$

$2 x^{4} - 32 y^{4} = 2 ({(x^{2})}^{2} - {(4 y^{2})}^{2})$ $color(white)(2x^4-32y^4) = 2((x^2)^2-(4y^2)^2)$

$2 x^{4} - 32 y^{4} = 2 (x^{2} - 4 y^{2}) (x^{2} + 4 y^{2})$ $color(white)(2x^4-32y^4) = 2(x^2-4y^2)(x^2+4y^2)$

$2 x^{4} - 32 y^{4} = 2 (x^{2} - {(2 y)}^{2}) (x^{2} + 4 y^{2})$ $color(white)(2x^4-32y^4) = 2(x^2-(2y)^2)(x^2+4y^2)$

$2 x^{4} - 32 y^{4} = 2 (x - 2 y) (x + 2 y) (x^{2} + 4 y^{2})$ $color(white)(2x^4-32y^4) = 2(x-2y)(x+2y)(x^2+4y^2)$

Science

Math

Humanities

... and beyond

How do you factor $2 x^{4} - 32 y^{4}$ $2x^4-32y^4$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 2x4−32y42x^4-32y^4?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor $2 x^{4} - 32 y^{4}$ $2x^4-32y^4$ ?