How do you factor $2 y^{2} - y - 15$ $2y^2 -y -15$ ?

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Answer 1 · 2016-08-14T16:15:36

$= (y - 3) (2 y + 5)$ $=(y-3)(2y+5)$

$2 y^{2} - y - 15$ $2y^2-y-15$

$= 2 y^{2} - 6 y + 5 y - 15$ $=2y^2-6y+5y-15$

$= 2 y (y - 3) + 5 (y - 3)$ $=2y(y-3)+5(y-3)$

$= (y - 3) (2 y + 5)$ $=(y-3)(2y+5)$

How do you factor 2y2−y−152y^2 -y -15?