How do you factor $32 x^{2} y + 48 x y^{2} + 40 z y + 60 y^{2}$ $32x^2y + 48xy^2 + 40zy +60y^2$ ?

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Answer 1 · 2015-09-13T12:02:21

You can do it like that

$32 x^{2} y + 48 x y^{2} + 40 z y + 60 y^{2} = 4 y \cdot (8 x^{2} + 12 x y + 15 y + 10 z)$ $32x^2y + 48xy^2 + 40zy +60y^2=4y*(8x^2+12xy+15y+10z)$

How do you factor 32x2y+48xy2+40zy+60y232x^2y + 48xy^2 + 40zy +60y^2?