How do you factor $36 - \frac{1}{9} r^{2}$ $36-1/9r^2$ ?

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How do you factor $36 - \frac{1}{9} r^{2}$ $36-1/9r^2$ ?

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Answer 1 · 2018-07-24T19:44:30

$\frac{1}{9} (18 - r) (18 + r)$ $1/9(18-r)(18+r)$

Explanation:

$take out a common factor \frac{1}{9}$ $"take out a "color(blue)"common factor "1/9$

$= \frac{1}{9} (324 - r^{2})$ $=1/9(324-r^2)$

$324 - r^{2} is a difference of squares$ $324-r^2" is a "color(blue)"difference of squares"$

$∙ x a^{2} - b^{2} = (a - b) (a + b)$ $•color(white)(x)a^2-b^2=(a-b)(a+b)$

$here a = \sqrt{324} = 18 and b = r$ $"here "a=sqrt324=18" and "b=r$

$36 - \frac{1}{9} r^{2} = \frac{1}{9} (18 - r) (18 + r)$ $36-1/9r^2=1/9(18-r)(18+r)$

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How do you factor $36 - \frac{1}{9} r^{2}$ $36-1/9r^2$ ?

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