How do you factor -36n^2+48n-15? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Alan P. Sep 1, 2016 -36n^2+48n-15=color(green)(-3(6n-5)(2n-1)) Explanation: -36n^2+48n-15 color(white)("XXX")=-(6n)^2+8(6n)-15 (replacing 6n with p temporarily) color(white)("XXX")=-p^2+8p-15 color(white)("XXX")=(-1)(p-5)(p-3) (restoring 6n back in place of p) color(white)("XXX")=(-1)(6n-5)(6n-3) color(white)("XXX")=(-3)(6n-5)(2n-1) Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor x^2+16x+48? How do you factor x^2-9x+20? Question #3fdac How do you factor 8+z^6? There is no GCF to be factor out, so is there another method to complete this? How do you factor 2t^2+7t+3? See all questions in Factorization of Quadratic Expressions Impact of this question 1540 views around the world You can reuse this answer Creative Commons License