How do you factor $36 x^{2} - 60 x + 25$ $36x^2-60x+25$ ?

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How do you factor $36 x^{2} - 60 x + 25$ $36x^2-60x+25$ ?

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Answer 1 · 2016-08-07T19:48:45

$= (6 x - 5) (6 x - 5)$ $=(6x-5)(6x-5)$

Explanation:

$36 x^{2} - 60 x + 25$ $36x^2-60x+25$
$= {(6 x)}^{2} - 2 (6 x) (5) + 5^{2}$ $=(6x)^2-2(6x)(5)+5^2$
$= {(6 x - 5)}^{2}$ $=(6x-5)^2$
$= (6 x - 5) (6 x - 5)$ $=(6x-5)(6x-5)$

Answer 2 · 2016-08-07T19:56:17

${(6 x - 5)}^{2}$ $(6x - 5)^2$

Explanation:

since your $x^{2}$ $x^2$ has a number in front of it, you will need to multiply that by 25 first. this gives you 900 so you now must find two numbers that add to $- 60$ $-60$ and multiply to $900$ $900$ . as luck would have it, $- 30$ $-30$ jumps out as the answer. break down the equation accordingly and factor from there.

$36 x^{2} - 60 x + 25$ $36x^2 - 60x + 25$

$36 x^{2} - 30 x - 30 x + 25$ $36x^2 - 30x - 30x + 25$

factor the frist two variables and then the second two

$36 x^{2} - 30 x - 30 x + 25$ $36x^2 - 30x - 30x + 25$

$6 x (6 x - 5) - 5 (6 x - 5)$ $6x(6x - 5) - 5(6x - 5)$

format with the numbers outside the brackets as one group and the leave the others as is.

$(6 x - 5) (6 x - 5)$ $(6x - 5)(6x - 5)$

this is a perfect square, ergo

${(6 x - 5)}^{2}$ $(6x - 5)^2$

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How do you factor $36 x^{2} - 60 x + 25$ $36x^2-60x+25$ ?

2 Answers

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How do you factor $36 x^{2} - 60 x + 25$ $36x^2-60x+25$ ?