How do you factor $36x^3-9x$ ?

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Answer 1 · 2016-05-20T10:52:53

$9x(2x-1)(2x+1)$

Note that $4xx9=36$

$=>9x(4x^2-1)$

Consider the standard form of $" "a^2-b^2=(a-b)(a+b)$

Note that $4x^2 -> (2x)^2" and " 1=1^2$

$9x[ (2x)^2-1^2]$

$9x(2x-1)(2x+1)$

How do you factor 36x^3-9x36x^3-9x?