How do you factor $39 x^{5} + 13 x^{3} - 78 x^{2}$ $39x^5+13x^3-78x^2$ ?

Question

How do you factor $39 x^{5} + 13 x^{3} - 78 x^{2}$ $39x^5+13x^3-78x^2$ ?

1 Answer

Impact of this question

1239 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-30T08:33:14

$13 x^{2} (3 x^{3} + x - 6)$ $13x^2(3x^3+x-6)$

Explanation:

Consider the $common factors$ $color(blue)"common factors"$ of the expression.

13 is a factor of all 3 coefficients and $x^{2}$ $x^2$ is common to all 3 terms.

$\Rightarrow common factor = 13 x^{2}$ $rArr color(blue)"common factor" =color(red)(13x^2)$

$\Rightarrow 13 x^{2} (3 x^{3} + x - 6) is factored form$ $rArrcolor(red)(13x^2)(3x^3+x-6)" is factored form"$

Science

Math

Humanities

... and beyond

How do you factor $39 x^{5} + 13 x^{3} - 78 x^{2}$ $39x^5+13x^3-78x^2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you factor 39x5+13x3−78x239x^5+13x^3-78x^2?

1 Answer

Explanation:

Related questions

Impact of this question

How do you factor $39 x^{5} + 13 x^{3} - 78 x^{2}$ $39x^5+13x^3-78x^2$ ?