How do you factor $3d^2+23d+14$ completely?

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Answer 1 · 2016-11-15T05:24:22

$d=-2/3$ and $d=-7$

$3d^2+23d+14=0$

$3d^2+21d+2d+14=0$

$3d(d+7)+2(d+7)=0$

$(3d+2)(d+7)=0$

$3d+2=0$ and $d+7=0$

$d=-2/3$ and $d=-7$

How do you factor 3d^2+23d+143d^2+23d+14 completely?