How do you factor $3 p^{3} - 21 p^{2} - p + 7$ $3p^3 - 21p^2 - p + 7$ ?

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Answer 1 · 2015-05-03T20:51:06

$3 p^{3} - 21 p^{2} - p + 7$ $color(red)(3p^3−21p^2)color(blue)(-p+7)$

$= (3 p^{2}) (p - 7) + (- 1) (p - 7)$ $=color(red)((3p^2)(p-7))+color(blue)((-1)(p-7))$

$= (3 p^{2} - 1) (p - 7)$ $=(3p^2-1)(p-7)$

How do you factor 3p^3 - 21p^2 - p + 73p3−21p2−p+73p^3 - 21p^2 - p + 7?