How do you factor $3 x^{2} - 19 x + 6 = 0$ $3x^2 - 19x +6 = 0$ ?

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How do you factor $3 x^{2} - 19 x + 6 = 0$ $3x^2 - 19x +6 = 0$ ?

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Answer 1 · 2016-10-28T21:14:00

$0 = 3 x^{2} - 19 x + 6 = (3 x - 1) (x - 6)$ $0 = 3x^2-19x+6 = (3x-1)(x-6)$

Explanation:

$3 x^{2} - 19 x + 6 = 0$ $3x^2-19x+6=0$

Use an AC Method:

Find a pair of factors of $A C = 3 \cdot 6 = 18$ $AC=3*6=18$ with sum $B = 19$ $B=19$

The pair $18, 1$ $18, 1$ works in that $18 + 1 = 19$ $18+1 = 19$ and $18 \cdot 1 = 18$ $18*1 = 18$ .

Use this pair to split the middle term and factor by grouping:

$3 x^{2} - 19 x + 6 = 3 x^{2} - 18 x - x + 6$ $3x^2-19x+6 = 3x^2-18x-x+6$

$3 x^{2} - 19 x + 6 = (3 x^{2} - 18 x) - (x - 6)$ $color(white)(3x^2-19x+6) = (3x^2-18x)-(x-6)$

$3 x^{2} - 19 x + 6 = 3 x (x - 6) - 1 (x - 6)$ $color(white)(3x^2-19x+6) = 3x(x-6)-1(x-6)$

$3 x^{2} - 19 x + 6 = (3 x - 1) (x - 6)$ $color(white)(3x^2-19x+6) = (3x-1)(x-6)$

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How do you factor $3 x^{2} - 19 x + 6 = 0$ $3x^2 - 19x +6 = 0$ ?

1 Answer

Explanation:

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Math

Humanities

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How do you factor 3x^2 - 19x +6 = 0 3x2−19x+6=03x^2 - 19x +6 = 0 ?

1 Answer

Explanation:

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How do you factor $3 x^{2} - 19 x + 6 = 0$ $3x^2 - 19x +6 = 0$ ?